2x^2-6.2x=16

Solution for 2x^2-6.2x=16 equation:

2x^2-6.2x=16

We move all terms to the left:

2x^2-6.2x-(16)=0

a = 2; b = -6.2; c = -16;
Δ = b2-4ac
Δ = -6.22-4·2·(-16)
Δ = 166.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6.2)-\sqrt{166.44}}{2*2}=\frac{6.2-\sqrt{166.44}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6.2)+\sqrt{166.44}}{2*2}=\frac{6.2+\sqrt{166.44}}{4}
$